Tuesday, May 11, 2010

Y13 Stars

Questions on Stars

1. any 4 from:


end of H burning/red giant/supergiant (1)

onset of He fusion/fusion of heavier nuclei (1)

gravitational collapse of core (1)

supernova explosion/ star explodes (1)

suitable mass limit (chanderasekha limit 1.4M) (1)

supported against gavity by neutron gas pressure/ ref to

Fermi pressure (1)

internal structure protons and electrons combined/ very

thin atmosphere/ metallic crust (1) 4

[4]



2. Any 5 from

red shift data for galaxies (accept stars) 1

calculate velocity from red shift 1

galaxies/ stars receding from Earth 1

distance data for galaxies/ stars 1

velocity α distance / v/r = constant / v-r graph straight line 1

universe began at a single point 1

[5]



3. (a) Any two

stars rotate around galactic centre 1

star with velocity component towards Earth 1

reference to motion/shape of galaxy 1

or other valid points eg blue shift

(b) Ho = 75/ 3 × 1019 s–1 1

t ≈ 1/ 2.5 × 10–18 1

t ≈ 4 × 1017 s 1

[5]



4. Hydrogen atoms/particles (1)

Collapse under gravity/ decrease of gpe (1)

Increase in kinetic energy/ temperature (1)

Fusion of protons (1)

Energy released/ ref. to E = ∆mc2 (1)

[5]





5. Any 6 from

Nuclear/hydrogen burning ends (1)

Mass > Chandrasekhar limit (1)

Expanding gas/planetary nebular/red giant (1)

Gravitational collapse /ref. to burning He or higher metals (1)

Correct ref. to (Fermi) pressure/ radiation pressure (1)

(must have ref. to pressure or force from radiation.)

Neutron star (neutron by itself, not enough) (1)

Correct reference to Schwarzschild radius/

allow mass> 3M/ allow ref. critical radius (1)

Black Hole (1) 6

[6]



6. Ho2 = (1 × 10–26 × 8 × π × 6.67 × 10–11) / 3 C1

Ho = 2.36 × 10–18 s–1 A1

[2]



7. (i) v/c = ∆λ / λ (1)

∆λ = 656.3 × 10–9 × 6.1 / 3 × 108 (ignore minus sign) (1)

∆λ = 1.33 × 10–14 m (1) 3

(ii) Graph: any 4 points plotted correctly (1)

all correct (1) 2

(iii) graph: draw curve, reasonable attempt (1) 1

(iv) Either point where star moves perpendicular to line of sight (1) 1

(v) time = 72 h ± (1)h (ecf read value from their graph ± 1 h) (1) 1

(vi) r = 3√(6.7 × 10–11 × 4 × 1030 × [72 × 3600]2/ 4π2) ecf (1)

r = 7.70 × 109 m ecf . (1) 2

(use of t = 72h 1/2)

[10]